(x^2-16)(x+1)=0

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Solution for (x^2-16)(x+1)=0 equation:


Simplifying
(x2 + -16)(x + 1) = 0

Reorder the terms:
(-16 + x2)(x + 1) = 0

Reorder the terms:
(-16 + x2)(1 + x) = 0

Multiply (-16 + x2) * (1 + x)
(-16(1 + x) + x2(1 + x)) = 0
((1 * -16 + x * -16) + x2(1 + x)) = 0
((-16 + -16x) + x2(1 + x)) = 0
(-16 + -16x + (1 * x2 + x * x2)) = 0
(-16 + -16x + (1x2 + x3)) = 0
(-16 + -16x + 1x2 + x3) = 0

Solving
-16 + -16x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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